You are viewing a single comment's thread. View all
0
PurestEvil on scored.co
1 year ago0 points(+0/-0)
It's like a simple form of Sudoku. You always do the line in which only 1 is missing.
1. Column: 9 - 4 / 8 * x = 7 --> x is 4.
4. Row: x + 1 + 7 - 4 = 8 -> x is 4. It's the same x as above.
3. Column: 6 - 5 + y - 7 = 3 -> y is 9.
3. Row: 8 - 5 = y - z * 2 -> y is 9 as above, therefore z is 3.
From here on you have 2 or 3 missing in every line. That means we have 5 equations each with 2 or 3 variables (6 in total). We need to figure out a viable constellation of values so that all 5 equations are correct. So first the ones with 2 missing (plus a simplified form for later):
I 1. Row: 9 + a - 6 = b - 3 | b = a + 6 | a = b - 6
II 2. Row: 4 + c * 5 - d = 6 | d = 5c - 2 | c = d/5 + 0.4
III 5. Row: 7 = e * 3 - f - 2 | f = 3e - 9 | e = 3 + f/3
IV 2. Column: a = c + 5 - 1 - e | a = c - e + 4 | e = c - a + 4 | c = a + e - 4
V 4. Column: b = d - 3 - 4 + f | b = d + f - 7 | d = b - f + 7 | f = b - d + 7
So we have to combine equations. In theory there can be multiple solutions, but we are restricted to integers from 1 to 9. Each variable must be one of those.
I and IV: c - e + 4 = b - 6 -> b = c - e + 10 | e = c - b + 10
I and V: a + 6 = d + f - 7 -> a = d + f - 13
II and V: 5c - 2 = b - f + 7 -> b = f + 5c - 9
II and IV: d/5 + 0.4 = a + e - 4 -> a = d/5 - e + 4.4 | e = d/5 - a + 4.4 | d = 5e + 5a - 22
III and IV: 3 + f/3 = c - a + 4 -> a = c - f/3 + 1
III and V: 3e - 9 = b - d + 7 -> b = 3e + d - 16
So what did we get? We managed to mix up variables. But otherwise nothing really. But if we get just 1 variable, we'd get all others too. The problem is that we can't. So we'll need to trial and error. But, we have a lot of options, and I assume some multi-dimensional math or drawing would be required. I could write a program to do it, or I'd have to spend time to figure out a way to meaningfully draw it to a paper.
But this is way too hard (almost impossible) for fifth grade. At that time I was by far the best in class in Math, and even I would have struggled with it. Maybe with trial and error, and with that 1-9 hint, but to do it properly takes quite some time and skills that are... possibly even inaccessible to 95%+ of people (non-humans not counted). And for the remaining ones it would take quite some time. ~1% or less would be able to do it without significant time.
1. Column: 9 - 4 / 8 * x = 7 --> x is 4.
4. Row: x + 1 + 7 - 4 = 8 -> x is 4. It's the same x as above.
3. Column: 6 - 5 + y - 7 = 3 -> y is 9.
3. Row: 8 - 5 = y - z * 2 -> y is 9 as above, therefore z is 3.
From here on you have 2 or 3 missing in every line. That means we have 5 equations each with 2 or 3 variables (6 in total). We need to figure out a viable constellation of values so that all 5 equations are correct. So first the ones with 2 missing (plus a simplified form for later):
I 1. Row: 9 + a - 6 = b - 3 | b = a + 6 | a = b - 6
II 2. Row: 4 + c * 5 - d = 6 | d = 5c - 2 | c = d/5 + 0.4
III 5. Row: 7 = e * 3 - f - 2 | f = 3e - 9 | e = 3 + f/3
IV 2. Column: a = c + 5 - 1 - e | a = c - e + 4 | e = c - a + 4 | c = a + e - 4
V 4. Column: b = d - 3 - 4 + f | b = d + f - 7 | d = b - f + 7 | f = b - d + 7
So we have to combine equations. In theory there can be multiple solutions, but we are restricted to integers from 1 to 9. Each variable must be one of those.
I and IV: c - e + 4 = b - 6 -> b = c - e + 10 | e = c - b + 10
I and V: a + 6 = d + f - 7 -> a = d + f - 13
II and V: 5c - 2 = b - f + 7 -> b = f + 5c - 9
II and IV: d/5 + 0.4 = a + e - 4 -> a = d/5 - e + 4.4 | e = d/5 - a + 4.4 | d = 5e + 5a - 22
III and IV: 3 + f/3 = c - a + 4 -> a = c - f/3 + 1
III and V: 3e - 9 = b - d + 7 -> b = 3e + d - 16
So what did we get? We managed to mix up variables. But otherwise nothing really. But if we get just 1 variable, we'd get all others too. The problem is that we can't. So we'll need to trial and error. But, we have a lot of options, and I assume some multi-dimensional math or drawing would be required. I could write a program to do it, or I'd have to spend time to figure out a way to meaningfully draw it to a paper.
But this is way too hard (almost impossible) for fifth grade. At that time I was by far the best in class in Math, and even I would have struggled with it. Maybe with trial and error, and with that 1-9 hint, but to do it properly takes quite some time and skills that are... possibly even inaccessible to 95%+ of people (non-humans not counted). And for the remaining ones it would take quite some time. ~1% or less would be able to do it without significant time.